#1359
Scrieţi un program care să citească o ecuație de un anumit tip și care să determine: a) tipul ecuației citite; b) soluția ecuației obținută prin rezolvarea acestei ecuații.
| Problema | ecuatie2 | Operații I/O |
ecuatie2.in/ecuatie2.out
|
|---|---|---|---|
| Limita timp | 0.1 secunde | Limita memorie |
Total: 64 MB
/
Stivă 8 MB
|
| Id soluție | #64858121 | Utilizator | |
| Fișier | ecuatie2.cpp | Dimensiune | 1.76 KB |
| Data încărcării | 07 Iunie 2026, 20:18 | Scor/rezultat | Eroare de compilare |
ecuatie2.cpp:100:28: warning: missing terminating " character 100 | case 1 : fout<<"1"<<" | ^ ecuatie2.cpp:100:28: error: missing terminating " character ecuatie2.cpp:101:1: warning: missing terminating " character 101 | "<<b-a; | ^ ecuatie2.cpp:101:1: error: missing terminating " character 101 | "<<b-a; | ^~~~~~~ ecuatie2.cpp:105:28: warning: missing terminating " character 105 | case 2 : fout<<"2"<<" | ^ ecuatie2.cpp:105:28: error: missing terminating " character ecuatie2.cpp:106:1: warning: missing terminating " character 106 | "<<b-a; | ^ ecuatie2.cpp:106:1: error: missing terminating " character 106 | "<<b-a; | ^~~~~~~ ecuatie2.cpp:110:28: warning: missing terminating " character 110 | case 3 : fout<<"3"<<" | ^ ecuatie2.cpp:110:28: error: missing terminating " character ecuatie2.cpp:111:1: warning: missing terminating " character 111 | "<<a-b; | ^ ecuatie2.cpp:111:1: error: missing terminating " character 111 | "<<a-b; | ^~~~~~~ ecuatie2.cpp:115:28: warning: missing terminating " character 115 | case 4 : fout<<"4"<<" | ^ ecuatie2.cpp:115:28: error: missing terminating " character ecuatie2.cpp:116:1: warning: missing terminating " character 116 | "<<a+b; | ^ ecuatie2.cpp:116:1: error: missing terminating " character 116 | "<<a+b; | ^~~~~~~ ecuatie2.cpp:120:28: warning: missing terminating " character 120 | case 5 : fout<<"5"<<" | ^ ecuatie2.cpp:120:28: error: missing terminating " character ecuatie2.cpp:121:1: warning: missing terminating " character 121 | "<<b/a; | ^ ecuatie2.cpp:121:1: error: missing terminating " character 121 | "<<b/a; | ^~~~~~~ ecuatie2.cpp:125:28: warning: missing terminating " character 125 | case 6 : fout<<"6"<<" | ^ ecuatie2.cpp:125:28: error: missing terminating " character ecuatie2.cpp:126:1: warning: missing terminating " character 126 | "<<b/a; | ^ ecuatie2.cpp:126:1: error: missing terminating " character 126 | "<<b/a; | ^~~~~~~ ecuatie2.cpp:130:28: warning: missing terminating " character 130 | case 7 : fout<<"7"<<" | ^ ecuatie2.cpp:130:28: error: missing terminating " character ecuatie2.cpp:131:1: warning: missing terminating " character 131 | "<<a/b; | ^ ecuatie2.cpp:131:1: error: missing terminating " character 131 | "<<a/b; | ^~~~~~~ ecuatie2.cpp:135:28: warning: missing terminating " character 135 | case 8 : fout<<"8"<<" | ^ ecuatie2.cpp:135:28: error: missing terminating " character ecuatie2.cpp:136:1: warning: missing terminating " character 136 | "<<a*b; | ^ ecuatie2.cpp:136:1: error: missing terminating " character 136 | "<<a*b; | ^~~~~~~ ecuatie2.cpp: In function ‘int main()’: ecuatie2.cpp:103:16: error: expected primary-expression before ‘break’ 103 | break; | ^~~~~ ecuatie2.cpp:108:16: error: expected primary-expression before ‘break’ 108 | break; | ^~~~~ ecuatie2.cpp:113:16: error: expected primary-expression before ‘break’ 113 | break; | ^~~~~ ecuatie2.cpp:118:16: error: expected primary-expression before ‘break’ 118 | break; | ^~~~~ ecuatie2.cpp:123:16: error: expected primary-expression before ‘break’ 123 | break; | ^~~~~ ecuatie2.cpp:128:16: error: expected primary-expression before ‘break’ 128 | break; | ^~~~~ ecuatie2.cpp:133:16: error: expected primary-expression before ‘break’ 133 | break; | ^~~~~ ecuatie2.cpp:138:16: error: expected primary-expression before ‘break’ 138 | break; | ^~~~~ ecuatie2.cpp:66:17: warning: unused variable ‘sol’ [-Wunused-variable] 66 | long a=0,b=0,sol; | ^~~ ecuatie2.cpp: In function ‘int TipEcuatie(char*, int)’: ecuatie2.cpp:54:1: warning: control reaches end of non-void function [-Wreturn-type] 54 | } | ^
www.pbinfo.ro permite evaluarea a două tipuri de probleme:
Problema ecuatie2 face parte din prima categorie. Soluția propusă de tine va fi evaluată astfel:
Suma punctajelor acordate pe testele utilizate pentru verificare este 100. Astfel, soluția ta poate obține cel mult 100 de puncte, caz în care se poate considera corectă.