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Detalii evaluare #64873827
Rezumat problemă
#241
Se dau două şiruri a şi b, cu n, respectiv m elemente, numere naturale, ordonate crescător. Să se construiască un al treilea şir, c, care să conţină, în ordine crescătoare, elementele din şirurile a şi b.
Candale Silviu (silviu) Detalii
| Problema | Interclasare | Operații I/O |
interclasare.in/interclasare.out
|
|---|---|---|---|
| Limita timp | 0.5 secunde | Limita memorie |
Total: 64 MB
/
Stivă 32 MB
|
| Id soluție | #64873827 | Utilizator |
Ianosiu Carla (CarlaNicola)
|
| Fișier | interclasare.cpp | Dimensiune | 1.63 KB |
| Data încărcării | 08 Iunie 2026, 21:25 | Scor/rezultat | Eroare de compilare |
Evaluare
Mesaj compilare
interclasare.cpp: In function ‘void afisare(long int, long int*)’: interclasare.cpp:54:10: error: no match for ‘operator>>’ (operand types are ‘std::ofstream’ {aka ‘std::basic_ofstream<char>’} and ‘long int’) 54 | fout >> sirC[0] >> " "; | ~~~~ ^~ ~~~~~~~ | | | | | long int | std::ofstream {aka std::basic_ofstream<char>} interclasare.cpp:54:10: note: candidate: ‘operator>>(int, long int)’ (built-in) 54 | fout >> sirC[0] >> " "; | ~~~~~^~~~~~~~~~ interclasare.cpp:54:10: note: no known conversion for argument 1 from ‘std::ofstream’ {aka ‘std::basic_ofstream<char>’} to ‘int’ In file included from /usr/include/c++/13/string:55, from /usr/include/c++/13/bits/locale_classes.h:40, from /usr/include/c++/13/bits/ios_base.h:41, from /usr/include/c++/13/ios:44, from /usr/include/c++/13/istream:40, from /usr/include/c++/13/fstream:40, from interclasare.cpp:1: /usr/include/c++/13/bits/basic_string.tcc:827:5: note: candidate: ‘template<class _CharT, class _Traits, class _Alloc> std::basic_istream<_CharT, _Traits>& std::operator>>(basic_istream<_CharT, _Traits>&, __cxx11::basic_string<_CharT, _Traits, _Alloc>&)’ 827 | operator>>(basic_istream<_CharT, _Traits>& __in, | ^~~~~~~~ /usr/include/c++/13/bits/basic_string.tcc:827:5: note: template argument deduction/substitution failed: interclasare.cpp:54:19: note: ‘std::ofstream’ {aka ‘std::basic_ofstream<char>’} is not derived from ‘std::basic_istream<_CharT, _Traits>’ 54 | fout >> sirC[0] >> " "; | ^ In file included from /usr/include/c++/13/istream:1106: /usr/include/c++/13/bits/istream.tcc:975:5: note: candidate: ‘template<class _CharT, class _Traits> std::basic_istream<_CharT, _Traits>& std::operator>>(basic_istream<_CharT, _Traits>&, _CharT&)’ 975 | operator>>(basic_istream<_CharT, _Traits>& __in, _CharT& __c) | ^~~~~~~~ /usr/include/c++/13/bits/istream.tcc:975:5: note: template argument deduction/substitution failed: interclasare.cpp:54:19: note: ‘std::ofstream’ {aka ‘std::basic_ofstream<char>’} is not derived from ‘std::basic_istream<_CharT, _Traits>’ 54 | fout >> sirC[0] >> " "; | ^ /usr/include/c++/13/istream:846:5: note: candidate: ‘template<class _Traits> std::basic_istream<char, _Traits>& std::operator>>(basic_istream<char, _Traits>&, unsigned char&)’ 846 | operator>>(basic_istream<char, _Traits>& __in, unsigned char& __c) | ^~~~~~~~ /usr/include/c++/13/istream:846:5: note: template argument deduction/substitution failed: interclasare.cpp:54:19: note: ‘std::ofstream’ {aka ‘std::basic_ofstream<char>’} is not derived from ‘std::basic_istream<char, _Traits>’ 54 | fout >> sirC[0] >> " "; | ^ /usr/include/c++/13/istream:851:5: note: candidate: ‘template<class _Traits> std::basic_istream<char, _Traits>& std::operator>>(basic_istream<char, _Traits>&, signed char&)’ 851 | operator>>(basic_istream<char, _Traits>& __in, signed char& __c) | ^~~~~~~~ /usr/include/c++/13/istream:851:5: note: template argument deduction/substitution failed: interclasare.cpp:54:19: note: ‘std::ofstream’ {aka ‘std::basic_ofstream<char>’} is not derived from ‘std::basic_istream<char, _Traits>’ 54 | fout >> sirC[0] >> " "; | ^ /usr/include/c++/13/istream:893:5: note: candidate: ‘template<class _CharT, class _Traits> std::basic_istream<_CharT, _Traits>& std::operator>>(basic_istream<_CharT, _Traits>&, _CharT*)’ 893 | operator>>(basic_istream<_CharT, _Traits>& __in, _CharT* __s) | ^~~~~~~~ /usr/include/c++/13/istream:893:5: note: template argument deduction/substitution failed: interclasare.cpp:54:19: note: ‘std::ofstream’ {aka ‘std::basic_ofstream<char>’} is not derived from ‘std::basic_istream<_CharT, _Traits>’ 54 | fout >> sirC[0] >> " "; | ^ /usr/include/c++/13/istream:936:5: note: candidate: ‘template<class _Traits> std::basic_istream<char, _Traits>& std::operator>>(basic_istream<char, _Traits>&, unsigned char*)’ 936 | operator>>(basic_istream<char, _Traits>& __in, unsigned char* __s) | ^~~~~~~~ /usr/include/c++/13/istream:936:5: note: template argument deduction/substitution failed: interclasare.cpp:54:19: note: ‘std::ofstream’ {aka ‘std::basic_ofstream<char>’} is not derived from ‘std::basic_istream<char, _Traits>’ 54 | fout >> sirC[0] >> " "; | ^ /usr/include/c++/13/istream:942:5: note: candidate: ‘template<class _Traits> std::basic_istream<char, _Traits>& std::operator>>(basic_istream<char, _Traits>&, signed char*)’ 942 | operator>>(basic_istream<char, _Traits>& __in, signed char* __s) | ^~~~~~~~ /usr/include/c++/13/istream:942:5: note: template argument deduction/substitution failed: interclasare.cpp:54:19: note: ‘std::ofstream’ {aka ‘std::basic_ofstream<char>’} is not derived from ‘std::basic_istream<char, _Traits>’ 54 | fout >> sirC[0] >> " "; | ^ /usr/include/c++/13/istream:1096:5: note: candidate: ‘template<class _Istream, class _Tp> _Istream&& std::operator>>(_Istream&&, _Tp&&)’ 1096 | operator>>(_Istream&& __is, _Tp&& __x) | ^~~~~~~~ /usr/include/c++/13/istream:1096:5: note: template argument deduction/substitution failed: /usr/include/c++/13/istream: In substitution of ‘template<class _Istream, class _Tp> _Istream&& std::operator>>(_Istream&&, _Tp&&) [with _Istream = std::basic_ofstream<char>&; _Tp = long int&]’: interclasare.cpp:54:19: required from here /usr/include/c++/13/istream:1096:5: error: no type named ‘type’ in ‘struct std::enable_if<false, void>’ interclasare.cpp: In function ‘int main()’: interclasare.cpp:75:12: error: invalid conversion from ‘long int’ to ‘long int*’ [-fpermissive] 75 | citire(nrElemA, sirA); | ^~~~~~~ | | | long int interclasare.cpp:8:22: note: initializing argument 1 of ‘void citire(long int*, long int&)’ 8 | void citire(long int sir[100000], long int & nrElem) | ~~~~~~~~~^~~~~~~~~~~ interclasare.cpp:75:21: error: invalid conversion from ‘long int*’ to ‘long int’ [-fpermissive] 75 | citire(nrElemA, sirA); | ^~~~ | | | long int* interclasare.cpp:8:46: note: initializing argument 2 of ‘void citire(long int*, long int&)’ 8 | void citire(long int sir[100000], long int & nrElem) | ~~~~~~~~~~~^~~~~~ interclasare.cpp:75:21: error: cannot bind rvalue ‘(long int)((long int*)(& sirA))’ to ‘long int&’ 75 | citire(nrElemA, sirA); | ^~~~ interclasare.cpp:76:12: error: invalid conversion from ‘long int’ to ‘long int*’ [-fpermissive] 76 | citire(nrElemB, sirB); | ^~~~~~~ | | | long int interclasare.cpp:8:22: note: initializing argument 1 of ‘void citire(long int*, long int&)’ 8 | void citire(long int sir[100000], long int & nrElem) | ~~~~~~~~~^~~~~~~~~~~ interclasare.cpp:76:21: error: invalid conversion from ‘long int*’ to ‘long int’ [-fpermissive] 76 | citire(nrElemB, sirB); | ^~~~ | | | long int* interclasare.cpp:8:46: note: initializing argument 2 of ‘void citire(long int*, long int&)’ 8 | void citire(long int sir[100000], long int & nrElem) | ~~~~~~~~~~~^~~~~~ interclasare.cpp:76:21: error: cannot bind rvalue ‘(long int)((long int*)(& sirB))’ to ‘long int&’ 76 | citire(nrElemB, sirB); | ^~~~
Cum funcționează evaluarea?
www.pbinfo.ro permite evaluarea a două tipuri de probleme:
- probleme la care rezolvarea presupune scrierea unui program complet
- probleme la care rezolvarea presupune scrierea unei secvențe de program - câteva instrucțiuni, o listă de declarații, una sau mai multe funcții, etc.
Problema Interclasare face parte din prima categorie. Soluția propusă de tine va fi evaluată astfel:
- Programul sursă este compilat folosind compilatorul corespunzător. Dacă în urma compilării se obțin erori sau avertismente, acestea sunt afișate în această pagină.
- Dacă programul a fost compilat, executabilul obținut va fi rulat, furnizându-i-se unul sau mai multe seturi de date de intrare, în concordanță cu restricțiile specifice problemei. Pentru fiecare set de date se obține un anumit punctaj, în raport cu corectitudinea soluției tale.
Suma punctajelor acordate pe testele utilizate pentru verificare este 100. Astfel, soluția ta poate obține cel mult 100 de puncte, caz în care se poate considera corectă.